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# In the following situation, determine whether you are asked to determine the number of permutations or combinations. then do the calculation how many ways are there to pick a starting five from a basketball team of twelve members? a. permutation; ps - 2520 b. combination; 1c, - 792 c. combination: 2cs - 2520 d. permutation; ps - 95040 HarleyHailey
There should only be 1 solution quetzaliescalona

yo answer should be 6 if im not mistaken

step-by-step explanation: hayleighsmall111

There are 95040 ways to chose the starting five players

The answer is d ⇒ Permutation; Ps - 95040

Step-by-step explanation:

* Lets explain the difference between permutations and combinations

- Both permutations and combinations are collections of objects

- Permutations are for lists (order matters)

- Combinations are for groups (order doesn't matter)

- A permutation is an ordered combination.

- Permutation is nPr, where n is the total number and r is the number

of choices

# Example: chose the first three students from the group of 10 students

n = 10 and r = 3,then 10P3 is 720

- Combinations is nCr, where n is the total number and r is the number

of the choices

# Example: chose a group of three students from the group of 10 students

n = 10 and r = 3,then 10C3 is 120

* Lets solve the problem

- We want to pick starting five players from a basketball team of

twelve players

∵ We will pick the starting five

∴ The order is important

∴ We will use the permutations

∵ The total number of the players is 12

∵ The number of choices is 5

∴ n = 12 and r = 5

∵ The number of ways is nPr

∴ 12P5 = 95040

∴ There are 95040 ways to chose the starting five players

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